Perform the indicated operation.
(3a2 - 7xy)(3a2 + 7xy)

Question

Asked 11/18/2014 12:48:20 AM

Updated 11/18/2014 1:24:08 AM

5 Answers/Comments

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Flagged by jeifunk [11/18/2014 1:21:18 AM]

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Question

Asked 11/18/2014 12:48:20 AM

Updated 11/18/2014 1:24:08 AM

5 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by jeifunk [11/18/2014 1:21:18 AM]

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8

(r + s)(r2 - rs + s2)

= r3 - r2s + rs2 + r2s - rs2 + s3

= r3 + s3

= r3 - r2s + rs2 + r2s - rs2 + s3

= r3 + s3

Added 11/18/2014 1:21:15 AM

This answer has been confirmed as correct and helpful.

8

2x2 + 11x + 15 = (2x + 5)(x + 3)

Added 11/18/2014 1:22:35 AM

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8

16x^4 + 56x^2 + 49 = (4x^2+7)^2

Added 11/18/2014 1:23:36 AM

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8

(2a2 - 8)(4a4 + 16a2 + 64) = 8a6 - 512

Added 11/18/2014 1:24:08 AM

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Factor this expression completely, then place the factors in the proper location on the grid.
x3y3 + z3

Question

Not Answered

Updated 11/18/2014 2:12:45 AM

1 Answer/Comment

Factor this expression completely, then place the factors in the proper location on the grid.
5x3 + 40y6

Question

Not Answered

Updated 11/18/2014 2:08:31 AM

1 Answer/Comment

Perform the indicated operation.
x3 x2
User: Perform the indicated operation.
(14x3y2z)4

Question

Updated 11/18/2014 2:05:47 AM

2 Answers/Comments

(14x^3y^2z)^4 = 38,416x^12y^8z^4

Added 11/18/2014 2:05:26 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/18/2014 2:32:52 AM]

Which are zeros of the following polynomial?
6x 2 - 11x - 10 = 0
x = 6, x = 10
x = ; x =
x = -2; x = 5
x = ; x =

Question

Updated 11/24/2014 12:49:26 AM

1 Answer/Comment

Which of the following polynomials has zeros at x = –4 and x = 7?
4x 2 - 7x - 11
4x 2 - 49
7x 2 - 4x + 28
x 2 - 3x - 28

Question

Updated 11/24/2014 12:47:32 AM

1 Answer/Comment

x^2 - 3x - 28 has zeros at x = –4 and x = 7.

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x - 7 = 0 or x + 4 = 0

x = 7 or x = -4

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x - 7 = 0 or x + 4 = 0

x = 7 or x = -4

Added 11/24/2014 12:47:32 AM

This answer has been confirmed as correct and helpful.

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